The ChemTeam provides study resources in all standard topics for students in high school and Advanced Placement chemistry.
You can check the answer to this problem using Google calculator: https://encrypted.google.com/search?q=convert+1.94+m%2Fs+to+miles%2Fhour&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a
The equation in question is √(3RT/M). All that is considered are the units on R, T and M in showing how the unit m/s (meters per second) arises.
In which we are given the masses of calcium, sulfur and oxygen in a compound and then asked to calculate the formula of the compound.
The grams of aluminum and chlorine that make of a compound are given and the empirical formula is asked for.
Three beta decay equations are given, the first two were shown in the video titled 'Beta Decay I' without any answers. A more modern symbol for the antineutrino replaces the zeros to the left of the Greek letter nu with a right-subscripted lower-case e. The e symbolizes that this is an electron antineutrino, as opposed to muon or tau antineutrinos. Cobalt-60 was the isotope used in the discovery of the nonconservation of parity: http://hyperphysics.phy-astr.gsu.edu/hbase/nuclear/betaex.html
In which two beta decay equations are written and two others are given without an answer. The answers are provided in the video titled "Beta Decay II." A more modern symbol for the antineutrino replaces the zeros to the left of the Greek letter nu with a right-subscripted lower-case e. The e symbolizes that this is an electron antineutrino, as opposed to muon or tau antineutrinos.
Three balanced alpha decay equations are shown. The first two were given without an answer in the video titled "Alpha Decay I."
Two balanced alpha decay equations are written and two additional isotope are given as problems with no answer. See Alpha Decay II for the answers.
Sorry for the long title. This problem gives you grams of a first sample and asks you to calculate the grams of a second sample which has the same number of atoms as the first sample. The key point: when the moles of the two samples are equal, the nmber of atoms are also equal.
However, this problem uses third-life rather than half-life. In doing the video, I meant to write the fraction one-third in two different steps of the solution and BOTH times I wrote one-half, then corrected it. I guess that comes from having done sooooo many half-life problems over the years.